Optimal. Leaf size=367 \[ -\frac {2 (a-2 b) \left (a^2+4 a b-4 b^2\right ) \tanh (e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{35 b^2 f}+\frac {\left (a^2-11 a b+8 b^2\right ) \sinh (e+f x) \cosh (e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{35 b f}-\frac {\left (a^2-11 a b+8 b^2\right ) \text {sech}(e+f x) \sqrt {a+b \sinh ^2(e+f x)} F\left (\tan ^{-1}(\sinh (e+f x))|1-\frac {b}{a}\right )}{35 b f \sqrt {\frac {\text {sech}^2(e+f x) \left (a+b \sinh ^2(e+f x)\right )}{a}}}+\frac {2 (a-2 b) \left (a^2+4 a b-4 b^2\right ) \text {sech}(e+f x) \sqrt {a+b \sinh ^2(e+f x)} E\left (\tan ^{-1}(\sinh (e+f x))|1-\frac {b}{a}\right )}{35 b^2 f \sqrt {\frac {\text {sech}^2(e+f x) \left (a+b \sinh ^2(e+f x)\right )}{a}}}+\frac {b \sinh ^5(e+f x) \cosh (e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{7 f}+\frac {2 (4 a-3 b) \sinh ^3(e+f x) \cosh (e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{35 f} \]
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Rubi [A] time = 0.47, antiderivative size = 367, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 7, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.280, Rules used = {3188, 477, 582, 531, 418, 492, 411} \[ -\frac {2 (a-2 b) \left (a^2+4 a b-4 b^2\right ) \tanh (e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{35 b^2 f}+\frac {\left (a^2-11 a b+8 b^2\right ) \sinh (e+f x) \cosh (e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{35 b f}-\frac {\left (a^2-11 a b+8 b^2\right ) \text {sech}(e+f x) \sqrt {a+b \sinh ^2(e+f x)} F\left (\tan ^{-1}(\sinh (e+f x))|1-\frac {b}{a}\right )}{35 b f \sqrt {\frac {\text {sech}^2(e+f x) \left (a+b \sinh ^2(e+f x)\right )}{a}}}+\frac {2 (a-2 b) \left (a^2+4 a b-4 b^2\right ) \text {sech}(e+f x) \sqrt {a+b \sinh ^2(e+f x)} E\left (\tan ^{-1}(\sinh (e+f x))|1-\frac {b}{a}\right )}{35 b^2 f \sqrt {\frac {\text {sech}^2(e+f x) \left (a+b \sinh ^2(e+f x)\right )}{a}}}+\frac {b \sinh ^5(e+f x) \cosh (e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{7 f}+\frac {2 (4 a-3 b) \sinh ^3(e+f x) \cosh (e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{35 f} \]
Antiderivative was successfully verified.
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Rule 411
Rule 418
Rule 477
Rule 492
Rule 531
Rule 582
Rule 3188
Rubi steps
\begin {align*} \int \sinh ^4(e+f x) \left (a+b \sinh ^2(e+f x)\right )^{3/2} \, dx &=\frac {\left (\sqrt {\cosh ^2(e+f x)} \text {sech}(e+f x)\right ) \operatorname {Subst}\left (\int \frac {x^4 \left (a+b x^2\right )^{3/2}}{\sqrt {1+x^2}} \, dx,x,\sinh (e+f x)\right )}{f}\\ &=\frac {b \cosh (e+f x) \sinh ^5(e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{7 f}+\frac {\left (\sqrt {\cosh ^2(e+f x)} \text {sech}(e+f x)\right ) \operatorname {Subst}\left (\int \frac {x^4 \left (a (7 a-5 b)+2 (4 a-3 b) b x^2\right )}{\sqrt {1+x^2} \sqrt {a+b x^2}} \, dx,x,\sinh (e+f x)\right )}{7 f}\\ &=\frac {2 (4 a-3 b) \cosh (e+f x) \sinh ^3(e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{35 f}+\frac {b \cosh (e+f x) \sinh ^5(e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{7 f}-\frac {\left (\sqrt {\cosh ^2(e+f x)} \text {sech}(e+f x)\right ) \operatorname {Subst}\left (\int \frac {x^2 \left (6 a (4 a-3 b) b-3 b \left (a^2-11 a b+8 b^2\right ) x^2\right )}{\sqrt {1+x^2} \sqrt {a+b x^2}} \, dx,x,\sinh (e+f x)\right )}{35 b f}\\ &=\frac {\left (a^2-11 a b+8 b^2\right ) \cosh (e+f x) \sinh (e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{35 b f}+\frac {2 (4 a-3 b) \cosh (e+f x) \sinh ^3(e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{35 f}+\frac {b \cosh (e+f x) \sinh ^5(e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{7 f}+\frac {\left (\sqrt {\cosh ^2(e+f x)} \text {sech}(e+f x)\right ) \operatorname {Subst}\left (\int \frac {-3 a b \left (a^2-11 a b+8 b^2\right )-6 b \left (a^3+2 a^2 b-12 a b^2+8 b^3\right ) x^2}{\sqrt {1+x^2} \sqrt {a+b x^2}} \, dx,x,\sinh (e+f x)\right )}{105 b^2 f}\\ &=\frac {\left (a^2-11 a b+8 b^2\right ) \cosh (e+f x) \sinh (e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{35 b f}+\frac {2 (4 a-3 b) \cosh (e+f x) \sinh ^3(e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{35 f}+\frac {b \cosh (e+f x) \sinh ^5(e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{7 f}-\frac {\left (a \left (a^2-11 a b+8 b^2\right ) \sqrt {\cosh ^2(e+f x)} \text {sech}(e+f x)\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {1+x^2} \sqrt {a+b x^2}} \, dx,x,\sinh (e+f x)\right )}{35 b f}-\frac {\left (2 \left (a^3+2 a^2 b-12 a b^2+8 b^3\right ) \sqrt {\cosh ^2(e+f x)} \text {sech}(e+f x)\right ) \operatorname {Subst}\left (\int \frac {x^2}{\sqrt {1+x^2} \sqrt {a+b x^2}} \, dx,x,\sinh (e+f x)\right )}{35 b f}\\ &=\frac {\left (a^2-11 a b+8 b^2\right ) \cosh (e+f x) \sinh (e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{35 b f}+\frac {2 (4 a-3 b) \cosh (e+f x) \sinh ^3(e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{35 f}+\frac {b \cosh (e+f x) \sinh ^5(e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{7 f}-\frac {\left (a^2-11 a b+8 b^2\right ) F\left (\tan ^{-1}(\sinh (e+f x))|1-\frac {b}{a}\right ) \text {sech}(e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{35 b f \sqrt {\frac {\text {sech}^2(e+f x) \left (a+b \sinh ^2(e+f x)\right )}{a}}}-\frac {2 \left (a^3+2 a^2 b-12 a b^2+8 b^3\right ) \sqrt {a+b \sinh ^2(e+f x)} \tanh (e+f x)}{35 b^2 f}+\frac {\left (2 \left (a^3+2 a^2 b-12 a b^2+8 b^3\right ) \sqrt {\cosh ^2(e+f x)} \text {sech}(e+f x)\right ) \operatorname {Subst}\left (\int \frac {\sqrt {a+b x^2}}{\left (1+x^2\right )^{3/2}} \, dx,x,\sinh (e+f x)\right )}{35 b^2 f}\\ &=\frac {\left (a^2-11 a b+8 b^2\right ) \cosh (e+f x) \sinh (e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{35 b f}+\frac {2 (4 a-3 b) \cosh (e+f x) \sinh ^3(e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{35 f}+\frac {b \cosh (e+f x) \sinh ^5(e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{7 f}+\frac {2 \left (a^3+2 a^2 b-12 a b^2+8 b^3\right ) E\left (\tan ^{-1}(\sinh (e+f x))|1-\frac {b}{a}\right ) \text {sech}(e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{35 b^2 f \sqrt {\frac {\text {sech}^2(e+f x) \left (a+b \sinh ^2(e+f x)\right )}{a}}}-\frac {\left (a^2-11 a b+8 b^2\right ) F\left (\tan ^{-1}(\sinh (e+f x))|1-\frac {b}{a}\right ) \text {sech}(e+f x) \sqrt {a+b \sinh ^2(e+f x)}}{35 b f \sqrt {\frac {\text {sech}^2(e+f x) \left (a+b \sinh ^2(e+f x)\right )}{a}}}-\frac {2 \left (a^3+2 a^2 b-12 a b^2+8 b^3\right ) \sqrt {a+b \sinh ^2(e+f x)} \tanh (e+f x)}{35 b^2 f}\\ \end {align*}
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Mathematica [C] time = 2.82, size = 262, normalized size = 0.71 \[ \frac {\sqrt {2} b \sinh (2 (e+f x)) \left (32 a^3+b \left (144 a^2-480 a b+299 b^2\right ) \cosh (2 (e+f x))-496 a^2 b+2 b^2 (26 a-27 b) \cosh (4 (e+f x))+684 a b^2+5 b^3 \cosh (6 (e+f x))-250 b^3\right )-64 i a \left (2 a^3+3 a^2 b-13 a b^2+8 b^3\right ) \sqrt {\frac {2 a+b \cosh (2 (e+f x))-b}{a}} F\left (i (e+f x)\left |\frac {b}{a}\right .\right )+128 i a \left (a^3+2 a^2 b-12 a b^2+8 b^3\right ) \sqrt {\frac {2 a+b \cosh (2 (e+f x))-b}{a}} E\left (i (e+f x)\left |\frac {b}{a}\right .\right )}{2240 b^2 f \sqrt {2 a+b \cosh (2 (e+f x))-b}} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.83, size = 0, normalized size = 0.00 \[ {\rm integral}\left ({\left (b \sinh \left (f x + e\right )^{6} + a \sinh \left (f x + e\right )^{4}\right )} \sqrt {b \sinh \left (f x + e\right )^{2} + a}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: TypeError} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.14, size = 743, normalized size = 2.02 \[ \frac {5 \sqrt {-\frac {b}{a}}\, b^{3} \sinh \left (f x +e \right ) \left (\cosh ^{8}\left (f x +e \right )\right )+\left (13 \sqrt {-\frac {b}{a}}\, a \,b^{2}-21 \sqrt {-\frac {b}{a}}\, b^{3}\right ) \left (\cosh ^{6}\left (f x +e \right )\right ) \sinh \left (f x +e \right )+\left (9 \sqrt {-\frac {b}{a}}\, a^{2} b -43 \sqrt {-\frac {b}{a}}\, a \,b^{2}+35 \sqrt {-\frac {b}{a}}\, b^{3}\right ) \left (\cosh ^{4}\left (f x +e \right )\right ) \sinh \left (f x +e \right )+\left (\sqrt {-\frac {b}{a}}\, a^{3}-20 \sqrt {-\frac {b}{a}}\, a^{2} b +38 \sqrt {-\frac {b}{a}}\, a \,b^{2}-19 \sqrt {-\frac {b}{a}}\, b^{3}\right ) \left (\cosh ^{2}\left (f x +e \right )\right ) \sinh \left (f x +e \right )+\sqrt {\frac {b \left (\cosh ^{2}\left (f x +e \right )\right )}{a}+\frac {a -b}{a}}\, \sqrt {\frac {\cosh \left (2 f x +2 e \right )}{2}+\frac {1}{2}}\, \EllipticF \left (\sinh \left (f x +e \right ) \sqrt {-\frac {b}{a}}, \sqrt {\frac {a}{b}}\right ) a^{3}+15 \sqrt {\frac {b \left (\cosh ^{2}\left (f x +e \right )\right )}{a}+\frac {a -b}{a}}\, \sqrt {\frac {\cosh \left (2 f x +2 e \right )}{2}+\frac {1}{2}}\, \EllipticF \left (\sinh \left (f x +e \right ) \sqrt {-\frac {b}{a}}, \sqrt {\frac {a}{b}}\right ) a^{2} b -32 \sqrt {\frac {b \left (\cosh ^{2}\left (f x +e \right )\right )}{a}+\frac {a -b}{a}}\, \sqrt {\frac {\cosh \left (2 f x +2 e \right )}{2}+\frac {1}{2}}\, \EllipticF \left (\sinh \left (f x +e \right ) \sqrt {-\frac {b}{a}}, \sqrt {\frac {a}{b}}\right ) a \,b^{2}+16 \sqrt {\frac {b \left (\cosh ^{2}\left (f x +e \right )\right )}{a}+\frac {a -b}{a}}\, \sqrt {\frac {\cosh \left (2 f x +2 e \right )}{2}+\frac {1}{2}}\, \EllipticF \left (\sinh \left (f x +e \right ) \sqrt {-\frac {b}{a}}, \sqrt {\frac {a}{b}}\right ) b^{3}-2 \sqrt {\frac {b \left (\cosh ^{2}\left (f x +e \right )\right )}{a}+\frac {a -b}{a}}\, \sqrt {\frac {\cosh \left (2 f x +2 e \right )}{2}+\frac {1}{2}}\, \EllipticE \left (\sinh \left (f x +e \right ) \sqrt {-\frac {b}{a}}, \sqrt {\frac {a}{b}}\right ) a^{3}-4 \sqrt {\frac {b \left (\cosh ^{2}\left (f x +e \right )\right )}{a}+\frac {a -b}{a}}\, \sqrt {\frac {\cosh \left (2 f x +2 e \right )}{2}+\frac {1}{2}}\, \EllipticE \left (\sinh \left (f x +e \right ) \sqrt {-\frac {b}{a}}, \sqrt {\frac {a}{b}}\right ) a^{2} b +24 \sqrt {\frac {b \left (\cosh ^{2}\left (f x +e \right )\right )}{a}+\frac {a -b}{a}}\, \sqrt {\frac {\cosh \left (2 f x +2 e \right )}{2}+\frac {1}{2}}\, \EllipticE \left (\sinh \left (f x +e \right ) \sqrt {-\frac {b}{a}}, \sqrt {\frac {a}{b}}\right ) a \,b^{2}-16 \sqrt {\frac {b \left (\cosh ^{2}\left (f x +e \right )\right )}{a}+\frac {a -b}{a}}\, \sqrt {\frac {\cosh \left (2 f x +2 e \right )}{2}+\frac {1}{2}}\, \EllipticE \left (\sinh \left (f x +e \right ) \sqrt {-\frac {b}{a}}, \sqrt {\frac {a}{b}}\right ) b^{3}}{35 b \sqrt {-\frac {b}{a}}\, \cosh \left (f x +e \right ) \sqrt {a +b \left (\sinh ^{2}\left (f x +e \right )\right )}\, f} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (b \sinh \left (f x + e\right )^{2} + a\right )}^{\frac {3}{2}} \sinh \left (f x + e\right )^{4}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int {\mathrm {sinh}\left (e+f\,x\right )}^4\,{\left (b\,{\mathrm {sinh}\left (e+f\,x\right )}^2+a\right )}^{3/2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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